In figure if ab ii cd and cd ii ef find ace
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In figure if ab ii cd and cd ii ef find ace
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WebApr 5, 2024 · Sum of the interior angles, ∠CEF + ∠ECD = 180°. 130° + ∠ECD = 180°. ∠ECD = 180° – 130°. ∠ECD = 50°. WebIn the given figure, if AB CD and CD EF, find ∠ACE. Solution The figure is given as follows: It is given that AB CD and CD EF Thus, and are alternate interior opposite angles. Therefore, Also, we have From the figure: From equations (i) and (ii): Hence, the required value for is. Lines and Angles Axioms Standard IX Mathematics
WebIn the Given Figure, If Ab De And Bd Fg Such that ∠Fgh = 125° and ∠B = 55°, Find X And Y. CBSE English Medium Class 9. Textbook Solutions 13776. Important Solutions 1. Question Bank Solutions 11126. Concept Notes & Videos 282 Syllabus. In the Given Figure, If Ab De And Bd Fg Such that ∠Fgh = 125° and ∠B = 55°, Find X And ... WebMay 1, 2024 · To find : ∠ACE. Proof: Since, EF ‖ CD and EC is a transversal and sum of the interior angles on the same side of a transversal is 180°. ∴ ∠FEC + ∠ECD = 180° 130° + ∠ECD = 180° ∠ECD = 180° – 130° ∠ECD = 50° Also, BA ‖ CD ∠BAC = ∠ACD = 70° [Alternate angles] But, ∠ACD = ∠ACE + ∠ECD 70° = ∠ACE + 50°
WebMar 22, 2024 · Now, AB CD & GE is transversal, Hence, ∠ AGE = ∠ GED ∠ AGE = 126° Now, Since AB is a line ∠ AGE + ∠ FGE = 180° 126° + ∠ FGE = 180° ∠ FGE = 180° – 126° ∠ FGE = 54° Now, ∠ GEF = ∠ GED – ∠ FED ∠ GEF = 126° – 90° ∠ FGE = 36° ∴ ∠AGE = 126°, ∠GEF = 36°, ∠FGE = 54°. Next: Ex 6.2, 4 Important → ... WebOct 10, 2024 · Solution: EF and CD are parallel ; CE is a transversal pass through the parallel lines EF and CD. Sum of angles in same side of transversal which passes through parallel lines is 180°. ∠ DCE + angle CEF = 180°. ∠ DCE + 130° = 180°. ∠ DCE = 180° − 130°. ∠ DCE = 50°. AB is parallel to CD.
WebJun 25, 2024 · Given : In the figure, AB CD and CD EF ∠BAC = 70°, ∠CEF = 130° ∵ EF CD ∴ ∠ECD + ∠CEF = 180° (Co-interior angles) ⇒ ∠ECD + 130° = 180° ∴ ∠ECD = 180° – 130° = 50° ∵ BA CD ∴ ∠BAC = ∠ACD (Alternate angles) ∴ ∠ACD = 70° (∵ ∠BAC = 70°) ∵ ∠ACE = ∠ACD – ∠ECD = 70° – 50° = 20° Question 4. In the figure, state which lines are parallel and …
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